In engines which work without condensation, and therefore with high pressure steam, we shall have = 618 c = 0.05 e + 0.05 To facilitate computation, the values of e' corresponding to all values of e, from e10 to e='90, are given in the following : In engines which work without expansion we have a e = 1 + c For condensing engines without expansion, we shall then have As the diameters of the cylinders of engines are generally expressed in inches, the corresponding areas of the pistons expressed in square feet are given in the following table, so that the values of A may be readily found: The practical application of the preceding formula will be shown by the following examples. EXAMPLES. 1. A 36-inch cylinder with 5 feet stroke is supplied by a boiler evaporating effectively 60 cubic feet of water per hour, and the piston makes 20 strokes per minute without expansion; — what is the power of the engine and the pressure of steam in the cylinder? Let it be assumed that r = 6 × 144 = 864 and m = 0·1. Since the engine is a condensing engine, we have b=164 and e'=3691399. By the formulæ (25.) and (26.) we have We'-VA (b + r) and since by the data we have W = 1 A = 7.069 V= 2n L = 40 × 5·5 = 220, the formula, by these substitutions, becomes Since e = 1, the pressure P of steam in the cylinder, by (18.), is which being the pressure in pounds per square foot, the pressure per square inch will be 15 lbs. 2. To find the effective evaporation necessary to produce a power of 80 horses with the same engine. Also, find the pressure of steam in the cylinder, the speed of the piston being the same. By the formula (32.), with the above substitutions, we have W= = 1.22. The evaporating power would therefore be only increased 22 per cent., while the working power of the engine would be increased nearly 40 per cent. The pressure P in the cylinder will be given, by (18.), as before. 1.22 3691399 2732; P = 1555.18 · 164 = inch. which is equivalent to 19 lbs. per square 3. What must be the diameter of a cylinder to work with a power of a hundred horses, supplied by a boiler evaporating effectively 70 cubic feet of water per hour, the mean speed of the piston being 240 feet per minute, and the steam being cut off at half stroke? Also, what will be the full pressure of steam on the piston? Taking, as in the former examples, m = 0·1, b = 164, and r=864, we shall have W=11 V=240, and by the column for condensing engines, in table, p. 519, we have e' = = 6029916, where e = 0.50. Making these substitutions in We': = we shall have 33000 H (1 + m) + VA (b + r), 1 × 60299163300000 × 1·1 + 240 × 1028 × A. Whence we find A = 13.8; and by the table, p. 520, the corresponding diameter of the cylinder will be 50 inches. If P' be the full pressure of the steam, we shall have, by (18.), which being in pounds per square foot, the pressure per square inch will be 161% lbs. INDEX. Air, elasticity of, 28. May be partially expelled from a vessel by the Atmospheric air, mechanical properties of, 38. Composition of, 253. Barometer gauge, 272. Barton's piston, 248. Beighton, his improvement of the atmospheric engine, 75. Black, Dr., his doctrine of latent heat, 93. Blasco de Garay, his contrivance to propel vessels, 16. The contrivance of, probably identical with that of Hero, 17. Blinkensop, his locomotive engine, 337. Blowing-box, 429. Blowing out, Seaward's method of, 454. |