An elementary treatise on MechanicsMacmillan, 1863 - 374 páginas |
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Página vi
... vertical , horizontal , centre of gravity , 69 ; there is one and only one centre of gravity for any system , 70 ; centre of parallel forces , 70 , Cor . 3 ; centre of gravity of a right line , a parallelogram , a triangle , perimeter ...
... vertical , horizontal , centre of gravity , 69 ; there is one and only one centre of gravity for any system , 70 ; centre of parallel forces , 70 , Cor . 3 ; centre of gravity of a right line , a parallelogram , a triangle , perimeter ...
Página 45
... vertical line passing through the centre of gravity of the body . ( See Chap . V. ) If more than three forces act on the body in one plane , the conditions of equilibrium given in Art . ( 38 ) or the equivalent forms given in Art . ( 39 ) ...
... vertical line passing through the centre of gravity of the body . ( See Chap . V. ) If more than three forces act on the body in one plane , the conditions of equilibrium given in Art . ( 38 ) or the equivalent forms given in Art . ( 39 ) ...
Página 46
... vertical line . Since the two tensions act through C , the third force must also pass through C , and therefore CG must be vertical ; this determines geometrically the position of the rod , and if we draw Gp parallel to AC , the sides ...
... vertical line . Since the two tensions act through C , the third force must also pass through C , and therefore CG must be vertical ; this determines geometrically the position of the rod , and if we draw Gp parallel to AC , the sides ...
Página 47
... vertical line through G , this vertical line must pass through C also , or CG must be vertical . This determines the position of equilibrium geometrically , and the tensions T and T ' ' might be found as in the last problem : the only ...
... vertical line through G , this vertical line must pass through C also , or CG must be vertical . This determines the position of equilibrium geometrically , and the tensions T and T ' ' might be found as in the last problem : the only ...
Página 48
... vertical line through C must pass through W ; and therefore the diagonal CWO of the rectangle CO must be vertical . Hence a — 0 = ¿ TBO = ¿ WOB == - .. 0 = 2α 2α- T π - a , ( i ) . Also , R : R ' : W = sin R ' CW : sin RCW : sin R ' CR ...
... vertical line through C must pass through W ; and therefore the diagonal CWO of the rectangle CO must be vertical . Hence a — 0 = ¿ TBO = ¿ WOB == - .. 0 = 2α 2α- T π - a , ( i ) . Also , R : R ' : W = sin R ' CW : sin RCW : sin R ' CR ...
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Términos y frases comunes
accelerating force angular points applied axis balance ball bisects body or system centre of gravity circle coefficient of friction conditions of equilibrium cos² curve cycloid cylinder determine diagonal distance elastic equal particles equation equi find the centre fixed point forces acting fulcrum funicular geometrical given heavy particles Hence horizontal plane impact inclined plane latus rectum length lever librium magnitude and direction mass middle point moving parabola parallel parallelogram parallelogram of forces parallelopiped Pcos perpendicular polygon position of equilibrium pressure pully pyramid radius represented resolved rest resultant right angles rough shew sides similar triangles sin² sliding smooth sphere straight line string passes student suppose surface system of forces system of particles tangent tension theorem three forces tion triangle uniform vertex vertical plane virtual velocity W's virtual weight
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Página 15 - If two forces acting at a point be represented in magnitude and direction by the...